From earth they would seem drifting in westerly direction.
Calculate the height of geostationary satellite from the earth s ground level.
Suspect the difference may be the result of different values used for g m earth and radius earth.
A geostationary orbit also referred to as a geosynchronous equatorial orbit geo is a circular geosynchronous orbit 35 786 kilometres 22 236 miles above earth s equator and following the direction of earth s rotation.
156 a satellite in such an orbit is at an altitude of approximately 35 786 km 22 236 mi above mean sea level.
Then the time period of satellite orbiting 2600 km above the earth s surface r earth 6400 km will appoximetely be.
B calculate the height at which the satellite orbits above the surface of the earth.
At 384 403 kilometers from the center of the earth the moon completes a single orbit in 28 days.
The height of the geostationary orbit is 35786 kilometers above earth in geostationary orbit the satellite moves with an orbital speed of 11068 km per hours.
The equation for orbital height is derived from newton s second law.
My results are slightly different a bit high on orbital altitude and a bit low on velocity.
An object in such an orbit has an orbital period equal to the earth s rotational period one sidereal day and so to ground observers it appears motionless in a fixed.
A geostationary satellite orbits around the earth in a circular orbit of radius 3600 km.
Nasa s aqua satellite for example requires about 99 minutes to orbit the earth at about 705 kilometers up while a weather satellite about 36 000 kilometers from earth s surface takes 23 hours 56 minutes and 4 seconds to complete an orbit.
Speed of a satellite in circular orbit orbital velocity period centripetal force physics problem duration.
A geostationary equatorial orbit geo is a circular geosynchronous orbit in the plane of the earth s equator with a radius of approximately 42 164 km 26 199 mi measured from the center of the earth.
The organic chemistry tutor 143 911 views 17 18.
A minimum of three satellites are needed to cover the entire earth super synchronous orbit is a disposal storage orbit above gso.
The radius of the earth is 6400km and its mass is 6x10 24 kg.
It maintains the same.
